Variation of g: Why You Weigh Less at the Equator
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Engineering Exams9 min readAug 21, 2026Updated Sep 13, 2026

Variation of g: Why You Weigh Less at the Equator

Variation of g: Why You Weigh Less at the Equator
9 min read · 1,720 words

In one line: variation of g: JEE/NEET Physics · Gravitation series · Part 7 of 8 · All parts →✪ Key points — the 30-second versionHeight: g' ≈ g(1 − 2h/R) — exact: gR²/.

Therefore, JEE/NEET Physics · Gravitation series · Part 7 of 9 · All parts →

✪ Key points — the 30-second version

  • Therefore, One recipe: your gravity = (mass beneath you) ÷ (distance from centre)²
  • Meanwhile, Up a mountain: g falls a little · Deep in a mine: g falls to zero at the centre
  • Meanwhile, Spinning Earth makes the equator’s g slightly weaker than the poles’
  • g runs from 9.780 (equator) to 9.832 (poles) — ‘9.8’ is an average in disguise
  • Consequently, Exact formula for height; the shortcut only works for small heights

Consequently, Stand on a spring balance at the equator, then at the North Pole — the same you weighs about 350 grams more at the Pole. Meanwhile, Not an instrument trick: g itself genuinely changes with height , depth , and latitude . NEET asks all three as direct formula questions. Part 7 of the Gravitation series — with one recipe behind all three.

In this card.

  1. However, The one recipe behind everything.
  2. Moreover, Going up: the mountain case.
  3. In fact, Going down: the mine case.
  4. Spinning: the equator case.
  5. What each letter means.
  6. Solved examples.
  7. Common mistakes.
  8. Notably, This physics in your daily life.
  9. Practice set.
  10. Recap.

The One Recipe Behind Everything.

g = (mass beneath you) ÷ (distance from centre)². every case in this card is just a careful edit of this one recipe

Furthermore, Your gravity depends on only two things: how much planet is beneath you. Meanwhile, How far you are from its centre. Specifically, Climb: mass same, distance bigger → g falls. Dig: distance smaller BUT mass beneath you shrinks too → g still falls. Spin: some gravity gets ‘spent’ holding you on the circle → felt g falls. Three variations, one recipe.

Going Up: The Mountain Case.

g’ = g·R²/(R+h)²  ≈  g(1 − 2h/R) for small h. the shortcut is a good estimate only when h is tiny compared to R

However, Climbing to height h moves you farther from the centre: divide by (R+h)² instead of R². Meanwhile, Calibration: at Everest’s top, g drops only 0.03 m/s² — tiny, because 8.8 km is truly tiny next to 6,400 km. But at h = R (one full radius up), the exact formula gives g/4 — while the shortcut would absurdly give −g. If h isn’t tiny, use the exact form. A wrong-sign answer is your alarm bell.

Going Down: The Mine Case.

g’ = g(1 − d/R). digging to the centre, g gently reaches zero

Moreover, Descend to depth d and something lovely happens: all the rock ABOVE your head cancels its own pull (a shell of uniform rock pulls you equally in all directions from inside — net zero). Only the ball of rock beneath you counts — and that ball shrinks as you descend. At the centre of the Earth: nothing beneath, pulls from every side cancel — g = 0. You would float at the centre of the Earth.

Spinning: The Equator Case.

g’ = g − ω²R·cos²λ. λ = latitude; zero effect at the poles, biggest at the equator

In fact, The spinning Earth carries you around a circle (biggest circle at the equator, shrinking to nothing at the poles). Going in a circle needs some inward pull — part of gravity is ‘spent’ as that inward pull. The balance you stand on reads less. The discount is small (0.34% at the equator) but permanent — and combined with Earth’s slight equatorial bulge, real g runs 9.780 (equator) to 9.832 (poles).

What Each Letter Means.

Letter.What it means (plain words).Value / unit.
g.gravity strength at the surface (the starting value).Earth: 9.8 m/s².
h / d.height climbed / depth dug.in metres.
ω.spin rate of Earth in radians per second (2π ÷ 24 hours).7.29 × 10⁻⁵.
λ (lambda).latitude — 0° at the equator, 90° at the poles.degrees.

Solved Examples.

✎ Easy — the free mark. g at depth d = R/2 (halfway to the centre)?

Notably, One substitution: g’ = 9.8 × (1 − ½) = 4.9 m/s².

In other words, Check: halfway down, half the ‘effective planet’ beneath you — linear, clean.

Answer: 4.9 m/s² (= g/2)

✎ Exam level — exact vs shortcut. g at height h = R?

Specifically, Exact: g’ = g·R²/(2R)² = g/4 = 2.45 m/s².

Indeed, Shortcut would say: g(1 − 2) = −g — nonsense! That’s the alarm: big h demands the exact formula. JEE tests exactly this discrimination.

Answer: g/4 = 2.45 m/s²

✎ JEE level — the spinning discount. By what fraction is equator g reduced by Earth’s spin? (R = 6.4×10⁶ m, one spin = 86,400 s).

In short, Step 1 — spin rate: ω = 2π/86,400 = 7.27×10⁻⁵ per second.

Similarly, Step 2 — the spent part: ω²R = (7.27×10⁻⁵)² × 6.4×10⁶ ≈ 0.034 m/s².

Therefore, Step 3 — fraction: 0.034/9.8 ≈ 0.34%.

Fun limit: if Earth spun ~17× faster (a day of 1.4 hours). The spent part would equal g itself — objects at the equator would float!

Answer: ≈ 0.34% reduction at the equator

⚠ Mistakes students make — and how to avoid them.

  • Meanwhile, Using the small-h shortcut for big h. It quietly returns nonsense (like −g). If h is a serious fraction of R, use gR²/(R+h)² exactly.
  • ‘g = 0 at the centre, so energy = 0 there too.’ No! Consequently, At the centre, gravity’s pull is zero but the trap is at its DEEPEST (energy −1.5GMm/R). Zero pull ≠ zero debt.
  • Degrees instead of radians for ω. The spin formula needs radians per second (2π per rotation). A degree slips in and every number is silently wrong.
  • Digging past the centre. The depth formula only applies inside the planet — d cannot exceed R.

This Physics in Your Daily Life.

◎ This physics in your daily life.

  • Furthermore, The gold-trader margin: a 70 kg person reads ~350 g lighter at the equator than at the poles on a spring balance — precision traders and calibration labs genuinely account for latitude.
  • Mineral and oil hunting: dense ore buried underground makes g slightly stronger above it. Companies map tiny g-variations to find oil and minerals — a whole industry built on this card.
  • However, ESA’s GOCE satellite mapped Earth’s gravity variations so precisely that ocean currents and melting ice show up in the data.
  • Deep gold mines (like South Africa’s 3.8-km ones) can measure the depth-effect with a simple pendulum — this card, tested underground.

Practice set (answers hidden — try first).

(NEET-level) g at the bottom of a mine d = R/1000:.
g(1 − 1/1000) → 0.999g — a 0.1% drop.
(JEE Main-level) g at height h = R:.
Exact formula: g/4. The shortcut would wrongly give −g.
(Concept) Where do you weigh most — equator, pole, or Everest’s summit?
The pole: no spin discount, no height loss, and closer to Earth’s centre.
(NEET-level) The depth where g becomes g/4:.
g(1 − d/R) = g/4 → d = 3R/4.
(Concept) At the centre of the Earth, your weight and the gravity trap are:.
Weight zero (pulls cancel), but the trap is at its deepest — energy −1.5GMm/R.
🧠 Memory tricks & everyday anchors — the 20-second revision

  • 🧠 One recipe chant: ‘mass beneath ÷ distance²’ — all three variations are edits of this.
  • 🧠 Height hits twice as hard: height uses 2h/R, depth uses just d/R.
  • 🧠 Centre of Earth: zero pull, deepest trap — ‘no slope at the bottom of the well’.
  • 🏠 Daily: you weigh ~350 g less at the equator than at the poles — gold traders account for it.
  • 🏠 Daily: oil companies map tiny g-changes to find hidden deposits — an entire industry on this card.
One idea, three doors — open whichever clicks for you
Same concept (why you weigh less at the equator), three different ways of seeing it. If one door confuses you, try the next — at least one will stick.
Door 1 · The story way

Sit on a spinning merry-go-round: you feel flung outward. Earth is a giant merry-go-round, and at the equator you ride the widest circle — maximum outward fling, subtracting from gravity’s pull. At the poles you stand on the axis: no spin, no fling, full weight.

Door 2 · The numbers way

Earth’s pull is ~9.83 m/s² at the poles and effectively ~9.78 m/s² at the equator — a 0.05 difference, of which spin contributes 0.034. On a 70 kg person that’s ~350 g lighter at the equator: a bag of flour’s worth, measurable on a good scale.

Door 3 · The picture way

Picture Earth as a spinning top seen from above the pole: circles of daily travel at every latitude, shrinking to a point at the pole. Each circle’s outward fling is biggest at the equator’s fat circle, zero at the pole’s point. Weigh yourself on different circles, get different weights.

Why is this happening at all? Why does spin reduce weight? Because part of gravity’s pull is already ‘spent’ keeping you circling the Earth each day — it’s the centripetal fee. Only the leftover pull presses you into the scale. The bigger your daily circle, the bigger the fee, the lighter you feel.
▶ Recap card — save for revision week.

  • one recipe: g = (mass beneath) ÷ (distance from centre)²
  • height: g’ = gR²/(R+h)² ≈ g(1 − 2h/R) — shortcut only for tiny h
  • depth: g’ = g(1 − d/R) — rock above cancels itself; g = 0 at the centre
  • spin: g’ = g − ω²R cos²λ — biggest discount at the equator (~0.34%)
  • real g: 9.780 (equator) to 9.832 (poles)

Frequently Asked Questions.

What should you know about The One Recipe Behind Everything?

What should you know about Going Up: The Mountain Case?

What should you know about Going Down: The Mine Case?

What should you know about Spinning: The Equator Case?

What should you know about Solved Examples?

Moreover, One substitution: g’ = 9.8 × (1 − ½) = 4.9 m/s². Check: halfway down, half the ‘effective planet’ beneath you — linear, clean. ✔ Using the small-h shortcut for big h. It quietly returns nonsense (like −g). If h is a serious fraction of R, use gR²/(R+h)² exactly.

References & authoritative sources

Source: compiled from official notifications, standard textbooks and our own mock-test analytics; last reviewed September 2026.

Quick revision

  • Therefore, One recipe: your gravity = (mass beneath you) ÷ (distance from centre)²
  • Meanwhile, Up a mountain: g falls a little · Deep in a mine: g falls to zero at the centre
  • Meanwhile, Spinning Earth makes the equator’s g slightly weaker than the poles’
  • g runs from 9.780 (equator) to 9.832 (poles) — ‘9.8’ is an average in disguise
  • Consequently, Exact formula for height; the shortcut only works for small heights
  • However, The one recipe behind everything.
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Sources & official references

External references for fact-checking and further reading.