JEE/NEET Physics · Electrostatics series · Part 6 of 8 · All parts →
- A capacitor = two conductors separated by an insulator, storing charge pairs
- C = Q/V — capacitance is charge stored per volt (‘how much per height’)
- Parallel plates: C = ε₀A/d — bigger plates, closer = more capacitance
- Series: like resistors in parallel (1/C adds); parallel: simple addition
- Energy stored: ½CV² — half of QV (charging always costs double)
Every camera flash, every defibrillator jump-start, every RAM bit holding a 1 — a capacitor is at work: two plates, a gap, and a startling talent for parking charge. Part 6 of the Electrostatics series.
- What a capacitor is
- What each letter means
- The parallel-plate formula
- Series and parallel combinations
- The energy question (the ½ surprise)
- Solved examples
- Common mistakes
- This physics in your daily life
- Practice set
- Recap
What a Capacitor Is
Two conductors (usually plates) facing each other across an insulating gap. Connect a battery: it pushes electrons onto one plate and pulls them off the other — one plate charges −Q, the other +Q, and the pair stores energy in the field between them. The defining ratio:
| Letter | What it means (plain words) | Value / unit |
|---|---|---|
| C | capacitance — how much charge per volt | farad (F); μF = 10⁻⁶ F typical |
| Q | charge stored on EACH plate (one +Q, one −Q) | coulombs |
| V | voltage (potential difference) across the plates | volts |
| A, d | plate area and separation | m², m |
The farad is huge — practical capacitors are microfarads. A 1 F capacitor at 1 V holds 1 C: remember from Part 1, that’s six billion billion electrons.
The Parallel-Plate Formula
Engineering in one line: want more storage? Make the plates bigger, bring them closer, or (next card) fill the gap with better material. Every capacitor catalog is this formula decorated.
Series and Parallel Combinations
| Arrangement | Rule | Same as resistors… | Result |
|---|---|---|---|
| Parallel (side-by-side) | C = C₁ + C₂ | in series | capacitance ADDS — bigger |
| Series (end-to-end) | 1/C = 1/C₁ + 1/C₂ | in parallel | SMALLER than the smallest |
Memory hook: series capacitors behave like parallel resistors (reciprocal rule) — the swapped behaviour trips everyone once. Intuition: parallel adds plate area (more C); series adds gap distances (less C).
The Energy Question (the ½ Surprise)
Why only half? Charging isn’t free lunch: the battery pushes every coulomb across the FULL final voltage (work = QV), but the stored energy is ½QV — the other half was spent pushing charge onto a rising hill. (In ideal circuits it dissipates in resistance; nothing is violated.)
Solved Examples
Q = CV = 2×10⁻⁶ × 12 = 24 μC. U = ½CV² = ½ × 2×10⁻⁶ × 144 = 144 μJ.
Check the ½: QV = 288 μJ; stored is half. ✔
Answer: Q = 24 μC; U = 144 μJ
Parallel: 4 + 4 = 8 μF (adds). Series: (4×4)/(4+4) = 2 μF (halves for two equal ones).
Note the swap vs resistors: two equal resistors in series ADD (2R); capacitors in series HALVE (C/2). ✔
Answer: parallel 8 μF; series 2 μF
Isolated → Q is locked (nowhere to flow). C = ε₀A/d → halves. V = Q/C → doubles. U = Q²/2C → doubles.
Where did the extra energy come from? YOU — pulling apart oppositely-charged plates takes work (they attract). If instead the battery STAYED connected, V would be locked, and Q, U would halve. The connected/isolated split is the master question of this chapter. ✔
Answer: isolated: Q same, C halves, V doubles, U doubles
- Q meaning total charge. Q is the charge on EACH plate (+Q and −Q); ‘total’ on both plates is zero.
- Series/parallel rules swapped with resistors. Capacitors: parallel adds directly, series adds reciprocals — the reverse of resistor intuition.
- Using ½QV with changing V mid-process. ½CV² is exact for the final state; for changing conditions, track which quantity is locked (Q if isolated, V if connected).
- Forgetting the ε₀ in C = ε₀A/d (or using cm for d). Units first — farads come out tiny.
This Physics in Your Daily Life
- Every camera flash: a battery slowly charges a capacitor; the flash dumps it in a millisecond — capacitors are ‘charge sponges’ that release faster than any battery can.
- Defibrillators: ~200 J stored at ~2 kV, released through the heart in milliseconds — ½CV² saving lives.
- Your keyboard and touchscreen: each key/touch point is a tiny capacitor; pressing changes C = ε₀A/d slightly — the device senses which one. Every tap is Part 6.
- RAM chips hold each bit as charge on a femtofarad capacitor — your computer’s short-term memory is billions of these cards.
- Power supplies and grid stability use room-sized capacitor banks to smooth voltage dips — the formula, industrial scale.
Practice set (answers hidden — try first)
(NEET-level) A 5 μF capacitor at 20 V. Q:
(NEET-level) Two 6 μF capacitors in series:
(JEE Main-level) Energy in 10 μF at 50 V:
(Concept) Plate separation halved (battery connected). C:
(JEE Main-level) Plate area doubled, separation doubled:
- C = Q/V; C = ε₀A/d
- U = ½CV²
- 🔣 C = Q/V — charge per volt (farad)
- 🔣 parallel plates: C = ε₀A/d — bigger & closer = more
- 🔣 parallel: C adds; series: reciprocals (swapped vs resistors)
- 🔣 energy: U = ½CV² = ½QV — half of QV always
- 🔣 isolated capacitor: Q locked; connected: V locked
- 🔁 C = Q/V (farads)
- 🔁 C = ε₀A/d for parallel plates
- 🔁 combinations swap resistor rules
- 🧠 Chant: ‘big plates, small gap, big C’.
- 🧠 Swap rule: ‘capacitors combine opposite to resistors’.
- 🧠 Half rule: ‘charge × voltage, but only half stays’.
- 🏠 Daily: camera flashes and defibrillators — ½CV² in a millisecond.
- 🏠 Daily: every touchscreen tap reads a change in C = ε₀A/d.
Quick revision
- A capacitor = two conductors separated by an insulator, storing charge pairs
- C = Q/V — capacitance is charge stored per volt (‘how much per height’)
- Parallel plates: C = ε₀A/d — bigger plates, closer = more capacitance
- Series: like resistors in parallel (1/C adds); parallel: simple addition
- Energy stored: ½CV² — half of QV (charging always costs double)
- The parallel-plate formula
Have a doubt on this topic?
