You are currently viewing Viscosity and Terminal Velocity: The Friction of Fluids
JEE Main and Advanced5 min readSep 4, 2026Updated Sep 5, 2026

Viscosity and Terminal Velocity: The Friction of Fluids

Viscosity and Terminal Velocity: The Friction of Fluids
5 min read · 976 words

JEE/NEET Physics · Mechanical Properties of Fluids series · Part 5 of 7 · All parts →

✪ Key points — the 30-second version

  • Viscosity = internal friction of a fluid — treacle high, water low, gases lower
  • Newton’s law of viscosity: F = −ηA(dv/dx) — force from speed differences between layers
  • Stokes’ law: a small sphere moving slowly through fluid feels F = 6πηrv
  • Terminal velocity: weight = buoyancy + drag → v_t = 2r²g(ρ − σ)/(9η)
  • Bigger raindrops fall faster (r²!); parachutes drop terminal velocity by raising area

Pour water and pour honey: one races, one oozes. The difference — viscosity — is friction INSIDE the fluid, and it’s why raindrops survive the fall and parachutes save lives. Part 5 of the Mechanical Properties of Fluids series.

In this card

  1. Viscosity: the internal brake
  2. Newton’s viscosity law
  3. Stokes’ law for spheres
  4. Terminal velocity
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap

Viscosity: The Internal Brake

Fluids flow in layers, and neighbouring layers rub. The rubbing force — viscosity — resists differences in speed between layers. Honey’s layers cling hard (η ≈ 10 Pa·s); water’s barely (10⁻³); air’s less still (2×10⁻⁵). Viscosity falls with temperature in liquids (warm honey pours) and rises in gases.

Newton’s Law of Viscosity

F = −ηA (dv/dx)drag ∝ viscosity × area × speed gradient
LetterWhat it means (plain words)Value / unit
η (eta)coefficient of viscosityPa·s (or poise: 1 P = 0.1 Pa·s)
dv/dxhow quickly speed changes between layersper metre
Acontact area of the layers

Stokes’ Law for Spheres

A small sphere moving slowly (gentle flow, no turbulence) through fluid feels drag F = 6πηrv — proportional to radius and speed. This simple law is the workhorse of falling-ball experiments.

Terminal Velocity

A falling sphere accelerates until drag + buoyancy exactly cancel weight — then it cruises at constant speed:

v_t = 2r²g(ρ − σ) / 9ηρ = sphere’s density, σ = fluid’s

The r² is dramatic: a 2× fatter raindrop falls 4× faster. Too big, and drops break apart — nature’s speed limit keeps rain gentle.

Solved Examples

✎ Easy — the oil layer. Two plates 1 mm apart; the top moves at 0.5 m/s; η = 0.5 Pa·s, area 0.2 m². Drag force?

F = ηA(v/d) = 0.5 × 0.2 × (0.5/0.001) = 50 N.

Answer: 50 N

✎ Exam level — Stokes check. A 2 mm radius steel ball (ρ = 8000) in oil (σ = 800, η = 1) (g = 10): terminal speed?

v_t = 2(0.002)²(10)(7200)/(9×1) = 2×4×10⁻⁶×72000/9.

= 576×10⁻⁴… = 0.064 m/s — a slow, watchable sink (that’s how η is measured!). ✔

Answer: ≈0.064 m/s

✎ JEE level — raindrop logic. Why don’t raindrops hit like bullets?

A 1 mm drop: v_t ≈ 4 m/s (walk-jog pace); a 5 mm would need ~100 m/s but shatters first.

Viscosity + breakup cap rain at gentle speeds — terminal velocity is a survival mechanism for the uncovered world. ✔

Answer: Terminal velocity caps raindrop speed

⚠ Mistakes students make — and how to avoid them

  • Using Stokes’ law for big or fast objects. F = 6πηrv holds only for small spheres in gentle (laminar) flow — turbulence changes the game.
  • Density mix-up in v_t. The formula carries (ρ − σ): the DIFFERENCE between sphere and fluid densities (buoyancy’s fingerprint).
  • Temperature forgetting. Liquid viscosity falls when heated; gas viscosity rises — opposite directions, classic concept question.
  • Terminal velocity ≠ zero acceleration at once. It’s approached asymptotically after a brief acceleration phase.

This Physics in Your Daily Life

◎ This physics in your daily life

  • Engine oils are graded by viscosity (20W-40…) — chosen to keep engine drag low cold AND protection high hot: viscosity-temperature engineering in every service station.
  • Parachutes — trade the skydiver’s ~200 km/h terminal velocity for ~20 km/h by multiplying drag area: terminal velocity as a life-or-death dial.
  • Paint, ketchup and shampoo formulation — thickeners tune η so paint sticks but levels and ketchup rests but pours: rheology industries.
  • Blood’s viscosity matters medically — too thick stresses the heart, too thin bruises: blood thinners are viscosity prescriptions.
  • Honey, syrup, and tea brewing — hot water extracts faster because warm fluids’ lower viscosity speeds diffusion and flow.
One idea, three doors — open whichever clicks for you
Same concept (why falling objects reach a final speed), three different ways of seeing it. If one door confuses you, try the next — at least one will stick.
Door 1 · The story way

Drop a stone from a plane: gravity pulls steadily, but air drag grows with speed — every km/h costs a little more push-back. The tug-of-war must end when drag’s bill exactly equals gravity’s allowance: from then on, income equals outgo and speed freezes. The sky has a price list, and every object settles at its own quoted rate.

Door 2 · The numbers way

Skydiver spread-eagle: ~55 m/s terminal. Same diver head-down (less area): ~90 m/s. With parachute: ~5 m/s. Same gravity, same mass — only the drag area changed, and the terminal speed moved tenfold.

Door 3 · The picture way

Graph velocity against time for a drop: starts rising as a curve, then flattens onto a ceiling — the terminal velocity asymptote. Change the radius (r² in the formula) and the ceiling moves; change the fluid and it moves again.

Why is this happening at all? Why does drag grow with speed at all? Because a faster object shears the fluid layers around it harder (viscosity’s dv/dx) and must also shove fluid out of its path each second (momentum transfer). Linear sum at low speeds (Stokes), quadratic dominance at high ones. Terminal velocity is simply where the drag curve crosses the gravity line — and the crossing always exists because drag grows unbounded while gravity doesn’t.

Practice set (answers hidden — try first)

(NEET-level) Terminal velocity is where acceleration =
Zero (weight = drag + buoyancy).
(JEE Main-level) Radius doubles (Stokes regime): v_t becomes
4× larger.
(NEET-level) Heating honey makes it:
Less viscous (flows easier).
(Concept) Stokes’ law applies to:
Small spheres, slow (laminar) flow.
(JEE Main-level) F = 6πηrv with η=0.8, r=1 mm, v=0.5: F =
6π×0.8×0.001×0.5 ≈ 7.5×10⁻³ N.
🧠 Memory tricks & everyday anchors — the 20-second revision

  • viscosity = layers’ internal friction
  • F = ηA·dv/dx (Newton)
  • Stokes: F = 6πηrv (small, slow spheres)
  • v_t = 2r²g(ρ−σ)/9η
  • liquids thin out when heated; gases thicken
  • 🔁 viscosity meaning and units
  • 🔁 Newton + Stokes formulas
  • 🔁 terminal velocity derivation idea
▶ Recap card — save for revision week

  • 🧠 Chant: ‘r-squared rules the fall’.
  • 🧠 Stokes: ‘six-pi-eta-r-v’.
  • 🏠 Daily: engine oil grades = viscosity choices.
  • 🏠 Daily: parachutes dial terminal velocity down.

Quick revision

  • Viscosity = internal friction of a fluid — treacle high, water low, gases lower
  • Newton’s law of viscosity: F = −ηA(dv/dx) — force from speed differences between layers
  • Stokes’ law: a small sphere moving slowly through fluid feels F = 6πηrv
  • Terminal velocity: weight = buoyancy + drag → v_t = 2r²g(ρ − σ)/(9η)
  • Bigger raindrops fall faster (r²!); parachutes drop terminal velocity by raising area
  • Viscosity: the internal brake
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