Physics: Work, Power and Energy

Complete series — 8 parts · Hmmnm!! · hmmnm.in

Work Done: When a Force Actually Achieves Something

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 1 of 8 · All parts →

✪ Key points — the 30-second version

Push a wall all day — exhausting, but physics says you did ZERO work. Push a trolley the same effort — physics says you did real work. The difference? In physics, 'work' isn't sweat — it's force achieving movement along its own direction. Part 1 of the Work, Energy & Power series — the card that powers the whole chapter.

In this card

  1. The simple idea: force × movement
  2. What each letter means
  3. The angle rule: only the matching part counts
  4. The zero-work surprises
  5. Positive and negative work
  6. Solved examples
  7. Common mistakes
  8. This physics in your daily life
  9. Practice set
  10. Recap

The Simple Idea: Force × Movement

Work measures transfer of energy by a force. The formula is almost embarrassingly simple — how hard you push × how far the thing moves in the direction you push. One newton of push through one metre = one joule of work. But the strictness hides two traps, and both surprise everyone.

What Each Letter Means

Work as energy flow: force + movement along it → energy transferred (positive in, negative out — friction's arrow points backwards)

YOUR PUSHF along motion W = F d cosθpositive work object's KEincreases friction: force OPPOSES motion → negative work → KE decreases

W = F × d × cos(angle)force × distance × the cosine of the angle between push-direction and motion-direction
Letter What it means (plain words) Value / unit
W work done — energy transferred by the force joules (J)
F the force applied newtons (N)
d distance the object MOVES (not how hard you tried!) metres
angle between the force's direction and the motion's direction 0° = full work; 90° = zero; 180° = negative

The Angle Rule: Only the Matching Part Counts

Pull a trolley with a slanted rope: only the forward part of your pull moves the trolley forward. The upward part just lightens it (no forward movement from that). cos(angle) keeps exactly the matching part: at 0° (pulling straight along) cos = 1, full work; at 60°, half your force counts; at 90°, cos = 0, nothing counts.

The Zero-Work Surprises

Surprise 1 — pushing a wall: huge force, zero movement → d = 0 → work = 0. Your muscles burn stored energy (that's biology), but no work is done ON the wall.

Surprise 2 — carrying a bag on flat ground: your upward hold-force is perpendicular to your forward walking → angle = 90° → cos = 0 → work by the holding force = zero. The bag moves horizontally; your force points up; they don't match.

Surprise 3 — an orbiting satellite: gravity pulls toward Earth; motion is along the orbit. For a circular orbit they're exactly perpendicular — gravity does zero work on a circular orbit. That's why the ISS never slows down.

Positive and Negative Work

Force along motion (0°): positive work — energy given. Force against motion (180°, like friction on a sliding box): negative work — energy taken away. The sign is bookkeeping of energy flow, and it decides entire questions.

Solved Examples

✎ Easy — the pull. A 50 N pull along the ground drags a box 4 m. Work?

Angle 0°, cos = 1: W = 50 × 4 = 200 J.

Feel it: 200 J ≈ the energy of a phone charger for a second — modest, sensible. ✔

Answer: 200 J

✎ Exam level — the slanted pull. The same 50 N pull at 60° above the ground, box still moves 4 m horizontally. Work by the pull?

Only the forward part counts: forward force = 50 × cos60° = 25 N.

W = 25 × 4 = 100 J — exactly half. The other 25 N (upward part) did zero work. ✔

Answer: 100 J

✎ JEE level — friction's negative bookkeeping. A 20 kg box slides 5 m across a floor (grip μ = 0.3, g = 10) and stops. Work by friction?

Friction fights the motion → 180° → negative work.

Size: friction = 0.3 × 200 = 60 N. W = −60 × 5 = −300 J.

Meaning: the box handed 300 J to the floor as heat — the energy bookkeeping balances. ✔

Answer: −300 J (energy removed)

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) A 100 N box is lifted 2 m straight up. Work by the lifting force:
W = 100 × 2 × cos0° = 200 J.
(NEET-level) A porter carries a 20 kg load 50 m on flat ground. Work by the holding force:
Force (up) ⊥ motion (horizontal) → zero.
(JEE Main-level) A 40 N force at 60° drags a body 10 m horizontally:
W = 40 × 10 × cos60° = 200 J.
(Concept) Work done by Earth's gravity on the ISS in one circular lap:
Zero — gravity is perpendicular to the orbital motion.
(NEET-level) Friction of 25 N acts on a box sliding 8 m. Work by friction:
Opposes motion → 25 × 8 with negative sign = −200 J.
🧠 Memory tricks & everyday anchors — the 20-second revision

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← Previous series: Rotational MotionPart 2: Kinetic Energy and the Work-Energy Theorem: The Great Shortcut →

Kinetic Energy and the Work-Energy Theorem: The Great Shortcut

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 2 of 8 · All parts →

✪ Key points — the 30-second version

A car at 60 km/h needs four times the distance to stop as at 30 km/h. Not twice — four times. That single fact kills accidents, and it comes from one formula: moving energy grows with the SQUARE of speed. Part 2 of the Work, Energy & Power series.

In this card

  1. Moving energy, simply
  2. What each letter means
  3. The work-energy theorem: the great shortcut
  4. The v² law and road safety
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap

Moving Energy, Simply

Anything moving carries energy of motion — kinetic energy (KE). It depends on mass and speed, but NOT equally: mass counts once, speed counts twice (squared):

KE = ½ × mass × speed²½mv² — the square is the whole personality
Letter What it means (plain words) Value / unit
KE kinetic energy — energy of motion joules (J)
m mass of the moving thing kg
v its SPEED m/s — always squared here

Feel the square: a 50 kg cyclist at 10 m/s has 2,500 J; at 20 m/s (only double) — 10,000 J, four times. Triple the speed, nine times the energy.

The Work-Energy Theorem: The Great Shortcut

total work on a body = its KE change  (W_total = ½mv² − ½mu²)add up all the work (positive and negative) — that's exactly how much the moving energy changed

Why this is gold: Newton's method needs force at every instant. The theorem doesn't — it only needs before and after speeds, whatever complicated path connected them. A curved water slide, a bumpy road, a rollercoaster: total work is the same, and the theorem skips every detail in between.

The v² Law and Road Safety

Stopping means removing all the KE, and brakes remove energy roughly at a steady rate over distance. KE ∝ v², so stopping distance ∝ speed². 30→60 km/h: energy ×4, distance ×4. This one line of physics explains speed limits, school-zone signs, and why 'he was only a bit faster' is never true.

Solved Examples

✎ Easy — the cyclist. A 50 kg cyclist at 10 m/s. KE? And at 20 m/s?

At 10: ½ × 50 × 100 = 2,500 J. At 20: ½ × 50 × 400 = 10,000 J.

Double speed, ×4 energy — the square, felt. ✔

Answer: 2,500 J → 10,000 J

✎ Exam level — the theorem in action. A 1,000 kg car at 20 m/s brakes to a stop. Total work by brakes?

KE change: 0 − ½(1000)(400) = −200,000 J.

Theorem: work by brakes = −200 kJ — the brakes REMOVED 200 kJ (as heat; brake discs glow on F1 cars for exactly this reason).

Follow-up: at 40 m/s the same car needs −800 kJ — and four times the stopping distance. ✔

Answer: W = −200 kJ (removed)

✎ JEE level — the slide. A child (30 kg) slides from rest down a frictionless 4 m slide. Speed at the bottom (g = 10)?

Theorem route (no forces needed): gravity's work = mgh = 30×10×4 = 1,200 J (the normal push does zero work — perpendicular). KE goes 0 → 1,200 J.

½(30)v² = 1,200 → v² = 80 → v ≈ 8.9 m/s.

Notice: the slide's shape never entered — curved, straight, wavy: same answer. That's the theorem's power. ✔

Answer: v ≈ 8.9 m/s, whatever the slide's shape

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) A 2 kg ball at 3 m/s. KE:
½ × 2 × 9 = 9 J.
(JEE Main-level) Speed tripled. KE becomes:
3² = 9 → nine times.
(NEET-level) A 500 kg bike at 20 m/s brakes to rest. Work by brakes:
0 − ½(500)(400) = −100 kJ.
(Concept) A box slides down a frictionless curved slide of height h. Bottom speed depends on:
Only h — the shape is irrelevant (work-energy theorem).
(JEE Main-level) Equal KE, masses 1 kg and 4 kg. Speed ratio:
½(1)v₁² = ½(4)v₂² → v₁ = 2v₂ → 2 : 1.
🧠 Memory tricks & everyday anchors — the 20-second revision

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← Part 1: Work Done: When a Force Actually Achieves SomethingPart 3: Potential Energy: Stored Work, Ready to Strike →

Potential Energy: Stored Work, Ready to Strike

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 3 of 8 · All parts →

✪ Key points — the 30-second version

Lift a brick to a rooftop — it quietly stores the work you did. Let it go — the stored energy returns as motion. Dams, rollercoasters, archer's bows: all run on this stored energy. Potential energy (PE) is work banked by changing a position — height or stretch. Part 3 of the Work, Energy & Power series.

In this card

  1. Height energy: mgh
  2. Spring energy: ½kx²
  3. What each letter means
  4. Conservative: path never matters
  5. The PE ↔ KE trade
  6. Solved examples
  7. Common mistakes
  8. This physics in your daily life
  9. Practice set
  10. Recap

Height Energy: mgh

PE_gravity = mass × g × height  (mgh)the work you did lifting — stored, waiting
Letter What it means (plain words) Value / unit
m mass being lifted kg
g gravity strength at the surface ≈ 10 m/s² (9.8 precise)
h height ABOVE YOUR CHOSEN ZERO LEVEL metres — you choose the zero!

Lifting a 1 kg brick up 1 m costs ~10 J — banked as PE, returnable on release. Note h is measured from a zero level you choose (the ground, a table, a roof) — only PE changes are physical, so pick the most convenient zero and stay consistent.

Spring Energy: ½kx²

PE_spring = ½ × stiffness × stretch²½kx² — stretch squared, like speed squared in KE
Letter What it means (plain words) Value / unit
k stiffness — how many newtons per metre of stretch N/m (a stiff spring has big k)
x stretch or squeeze from natural length metres — always squared

Stretch a spring double: four times the stored energy. Compress triple: nine times. The square makes spring energy grow brutally — why a fully compressed loaded spring is genuinely dangerous.

Conservative: Path Never Matters

Gravity has a beautiful property: the work it does depends ONLY on height change — not the route. Lift a brick straight up 2 m or carry it up a spiral ramp 2 m: gravity's PE change is identical (mgh both ways). Forces like this are called conservative; they allow the free PE↔KE trading of Part 4. Friction is the opposite: its work depends on path length — energy leaks away and never returns.

The PE ↔ KE Trade

Drop the brick: PE (mgh) converts to KE (½mv²). Swing a pendulum: height energy ↔ motion energy, back and forth. Stretch a bow: your work → spring PE → arrow KE. All day, the universe trades between stored and moving energy — Part 4 makes the ledger exact.

Solved Examples

✎ Easy — the brick. A 2 kg brick lifted 5 m (g = 10). PE stored?

Direct: mgh = 2 × 10 × 5 = 100 J.

Check: 100 J banked = the KE it will have falling back — 100 = ½(2)v² → v = 10 m/s. ✔

Answer: 100 J

✎ Exam level — the spring. A spring of stiffness 200 N/m stretched 10 cm. Stored energy? And at 20 cm?

At 10 cm: ½(200)(0.1²) = 1 J. At 20 cm: ½(200)(0.2²) = 4 J.

Double stretch = ×4 energy — the square again. ✔

Answer: 1 J → 4 J (double stretch, ×4)

✎ JEE level — combined store. A 0.5 kg ball is placed on a vertical spring (k = 500 N/m) compressed 20 cm, then released. Max height above the release point (g = 10)?

Energy ledger: spring PE → height PE. ½(500)(0.2²) = 10 J = mgh → 10 = 0.5 × 10 × h.

h = 2 m.

Check: spring gives back everything it stored (ideal spring) — 10 J lifts 0.5 kg by 2 m. ✔

Answer: rises 2 m

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) A 5 kg bag on a 3 m table (zero at floor). PE:
5 × 10 × 3 = 150 J.
(JEE Main-level) Spring k = 800 N/m compressed 5 cm. Energy:
½ × 800 × (0.05)² = 1 J.
(Concept) Lifting a stone 2 m straight vs along a 5 m ramp (no friction): gravity's PE gain is:
Identical — 2mg in both cases (path-free).
(NEET-level) Doubling a spring's stretch multiplies stored energy by:
4 (x²).
(JEE Main-level) A 1 kg ball dropped from 20 m: KE at the ground (no air):
All mgh → 200 J → v = 20 m/s (zero level at ground).
🧠 Memory tricks & everyday anchors — the 20-second revision

▶ Recap card — save for revision week

← Part 2: Kinetic Energy and the Work-Energy Theorem: The Great ShortcutPart 4: Conservation of Energy: The Universe's Perfect Bookkeeping →

Conservation of Energy: The Universe's Perfect Bookkeeping

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 4 of 8 · All parts →

✪ Key points — the 30-second version

Drop anything — a feather (in vacuum) or an elephant — from the same height, and both hit the ground at the same speed. Mass doesn't even enter the answer. That's energy conservation at work: the universe's most reliable bookkeeping. Part 4 of the Work, Energy & Power series.

In this card

  1. The one rule
  2. What each letter means
  3. The famous result: v = √(2gh), no mass anywhere
  4. When friction leaks the ledger
  5. The pendulum's endless trade
  6. Solved examples
  7. Common mistakes
  8. This physics in your daily life
  9. Practice set
  10. Recap

The One Rule

The energy see-saw: what motion loses, height gains — the total never changes (until friction leaks it as heat)

total = KE + PE (constant) KEmax PE 0 bottom of swing — all motion KE 0 PEmax top of swing — all stored

KE + PE = constant  (when only gravity/springs act)motion energy + stored energy = unchanging total
Letter What it means (plain words) Value / unit
KE motion energy ½mv² J
PE stored energy: mgh (height) and/or ½kx² (spring) J
friction (if present) the leak: total drops by friction × distance the only common spoiler

Read it as a see-saw: what KE loses, PE gains, exactly. Total never changes (with only gravity/springs). With friction, the total still doesn't vanish — it leaks out as heat: mechanical energy lost = friction force × distance slid.

The Famous Result: v = √(2gh), No Mass Anywhere

Drop from height h: mgh = ½mv² → divide both sides by m — mass cancels completely → v = √(2gh). Heavy or light, same landing speed (in vacuum). From 20 m: v = √400 = 20 m/s. From 45 m (with g = 10): 30 m/s. One line, no mass, no time — the most useful result in the chapter.

When Friction Leaks the Ledger

Real slides and roads have friction. The bookkeeping then reads: (KE + PE)_start = (KE + PE)_end + friction × distance. The leak isn't lost — it's heat (why brake discs glow, why rubbing warms hands). Questions love this: 'how far does it slide before stopping?' — the leak formula answers in one line.

The Pendulum's Endless Trade

A pendulum swings because energy endlessly converts: maximum height (all PE, still) → bottom (all KE, fastest) → the other side's height (all PE again). With zero friction it would swing forever; real pendulums leak tiny heat each swing — that's why clocks needed winding.

Solved Examples

✎ Easy — the drop. Speed after falling 45 m (no air, g = 10)?

Famous result: v = √(2gh) = √(2 × 10 × 45) = √900.

v = 30 m/s — no mass needed, ever. ✔

Answer: 30 m/s

✎ Exam level — the ramp with friction. A 2 kg block slides from rest down a 3 m ramp (angle: height = 1.5 m) with friction 4 N acting along a 3 m path. Speed at the bottom (g = 10)?

Ledger: start PE = 2 × 10 × 1.5 = 30 J. Leak = friction × distance = 4 × 3 = 12 J. Remaining for KE = 18 J.

½(2)v² = 18 → v = √18 ≈ 4.24 m/s.

Check: without friction it'd be √30 ≈ 5.48 — friction slowed it, as it must. ✔

Answer: v ≈ 4.24 m/s

✎ JEE level — the loop. A bead slides from rest at height h on a frictionless track with a vertical loop of radius R at the bottom. Minimum h to complete the loop?

Two conditions meet: at the loop's top, gravity supplies the needed centripetal push: mg = mv²/R → v²_top = gR. Energy: mg·h = mg·(2R) + ½m·gR → h = 2R + R/2.

h = 2.5R.

This is the classic rollercoaster design number — five-halves the loop radius (in practice more, for friction). ✔

Answer: h = 2.5R (the rollercoaster rule)

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) Speed after a 20 m free fall (g = 10):
√(2×10×20) = 20 m/s.
(JEE Main-level) A 1 kg block slides 5 m on flat ground against friction 6 N, starting at 8 m/s. It stops after:
KE = ½(1)(64) = 32 J = 6 × d → d ≈ 5.33 m.
(Concept) A pendulum's speed is maximum at:
The lowest point — all PE traded into KE.
(JEE Main-level) Loop-the-loop minimum release height (loop radius R, frictionless):
2.5R.
(Concept) With friction present, 'energy is conserved' — true or false?
Mechanical energy: false (leaks as heat). Total energy including heat: always true.
🧠 Memory tricks & everyday anchors — the 20-second revision

▶ Recap card — save for revision week

← Part 3: Potential Energy: Stored Work, Ready to StrikePart 5: Power and Efficiency: How FAST You Can Do the Work →

Power and Efficiency: How FAST You Can Do the Work

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 5 of 8 · All parts →

✪ Key points — the 30-second version

Two students carry the same 20 kg load up the same stairs — identical work. One takes 1 minute, the other takes 10 seconds. Same work, wildly different POWER. Power is the speed of doing work — and it's what engines, motors and athletes are actually rated in. Part 5 of the Work, Energy & Power series.

In this card

  1. Power, simply
  2. What each letter means
  3. The two workhorse formulas
  4. Efficiency: nothing is 100%
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap

Power, Simply

Power = work ÷ time  (P = W/t)how many joules per second — the pace of energy transfer
Letter What it means (plain words) Value / unit
P power watts (W) = joules/second
W work (or energy) delivered joules
t time taken seconds

Feel the numbers: a phone charger ~20 W, a ceiling fan ~75 W, a microwave ~1,000 W, a car at highway pace ~20,000 W, a cricket ball's throw delivered in 0.1 s ~ 1,000 W momentarily. Horsepower (car specs) = 746 W.

The Two Workhorse Formulas

P = force × speed  (Fv)  ·  lifting: P = mgh/tFv: engines and motors; mgh/t: pumps, stairs, cranes

P = Fv is why cars struggle uphill: at fixed engine power, more needed force (climbing) forces less speed. It's also why you slow down when cycling into a headwind — same legs (power), more force needed, so speed must drop.

Efficiency: Nothing Is 100%

efficiency = useful energy out ÷ total energy inalways below 100% — the missing part becomes heat/noise

A car engine is ~25-35% efficient (most fuel energy becomes heat); an LED bulb ~40-50% (vs an old filament bulb's ~5% to light); an electric motor ~85-95%. Efficiency questions are pure percentage bookkeeping — keep the 'useful' clear.

Solved Examples

✎ Easy — the stair climb. A 60 kg student climbs 4 m of stairs in 10 s (g = 10). Average power?

Work: mgh = 60 × 10 × 4 = 2,400 J. Power: 2,400/10 = 240 W — about three fans' worth, sustained by legs. ✔

Answer: 240 W

✎ Exam level — the engine. A car engine delivers 40 kW at a steady 20 m/s. The driving force?

P = Fv: F = 40,000/20 = 2,000 N.

Check the physics: steady speed means this force exactly balances air + road resistance. Need more force (uphill)? Speed must fall — power is fixed. ✔

Answer: 2,000 N

✎ JEE level — efficiency chain. A pump motor (efficiency 80%) fills a tank with 10,000 kg of water lifted 20 m in 500 s. Electric power drawn (g = 10)?

Useful output: mgh = 10⁷ J; useful power = 10⁷/500 = 20 kW.

Efficiency 80%: input = 20/0.8 = 25 kW.

The missing 5 kW = motor heat — that's what the 80% meant. ✔

Answer: 25 kW drawn from the grid

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) A 50 kg person climbs 5 m in 25 s. Power (g = 10):
mgh/t = 2,500/25 = 100 W.
(JEE Main-level) An engine of 25 kW pushes a car at 10 m/s. Driving force:
F = P/v = 2,500 N.
(NEET-level) A 2 kW heater runs 3 hours. Energy consumed:
2 × 3 = 6 kWh = 6 units.
(JEE Main-level) A motor draws 5 kW to deliver 4 kW useful. Efficiency:
4/5 = 80%.
(Concept) At fixed engine power, climbing a hill, the car's speed:
Falls — more force needed, P = Fv fixed.
🧠 Memory tricks & everyday anchors — the 20-second revision

▶ Recap card — save for revision week

← Part 4: Conservation of Energy: The Universe's Perfect BookkeepingPart 6: Collisions: The Great Sorting — What Survives, What Dies →

Collisions: The Great Sorting — What Survives, What Dies

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 6 of 8 · All parts →

✪ Key points — the 30-second version

In every crash — a car wreck, a cricket ball on a bat, two ice pucks — one quantity ALWAYS survives the impact untouched, while another usually dies. Knowing which is which solves every collision question in one line each. Part 6 of the Work, Energy & Power series.

In this card

  1. The survivor: momentum
  2. The casualty: kinetic energy
  3. The three types of collision
  4. Equal masses in elastic hits: the neat swap
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap

The Survivor: Momentum

The collision sorting: momentum (blue) ALWAYS survives; kinetic energy (orange) dies in every real crash

2 kg 4 kg 6 m/s BEFORE: momentum 12, KE 36 J stuck together → 2 m/s AFTER: momentum 12 ✓ KE 12 J (24 J → heat)

total (mass × velocity) before = total aftermomentum — the 'quantity of motion' — survives every collision, no exceptions

Why so unbreakable: it's Newton's third law bookkeeping. During the crash, the two bodies push each other with equal, opposite forces for the same time — the changes cancel exactly. Whatever happens inside the crash (denting, heat, sound), the total motion-quantity is locked.

The Casualty: Kinetic Energy

Unlike momentum, KE is a one-direction street: the crash can convert it into heat, dents, and sound — never back. So the sorting is simple:

Type Momentum Kinetic energy Example
Elastic survives survives TOO (ideal) steel balls, gas molecules, billiards (near)
Inelastic survives partially dies most real hits — cricket ball, cars
Perfectly inelastic survives maximum loss — bodies STICK coupled train wagons, ball in mud

Equal Masses in Elastic Hits: The Neat Swap

Beautiful shortcut: equal masses colliding elastically simply exchange velocities. The moving one stops; the stopped one moves off with the first one's speed. Newton's cradle shows it in slow, clicking elegance.

Solved Examples

✎ Easy — the stick-together. A 2 kg ball at 6 m/s hits a stationary 4 kg ball; they stick. Common velocity?

Momentum survivor: (2×6) + 0 = (2+4)v → 12 = 6v.

v = 2 m/s.

Answer: 2 m/s

✎ Exam level — the energy audit. Same collision: how much KE died?

Before: ½(2)(36) = 36 J. After: ½(6)(4) = 12 J.

24 J died → heat and dent (67% of the energy!).

The pattern: momentum bookkeeping gave the speed; energy bookkeeping gives the loss — always two separate questions. ✔

Answer: 24 J lost (to heat/deformation)

✎ JEE level — elastic, unequal masses. A 1 kg ball at 4 m/s hits a stationary 3 kg ball elastically. Both final speeds?

Momentum: 1(4) = v₁ + 3v₂.

Elastic adds KE: 8 = ½v₁² + (3/2)v₂².

Solve the pair: v₁ = 4−3v₂ → substitute → v₂ = 2 m/s, v₁ = −2 m/s.

Read it: the light ball BOUNCES BACK (−2), the heavy one crawls forward (2). Light things bounce off heavy things — cricket ball vs bat, you vs a truck. ✔

Answer: 1 kg ball: −2 m/s (rebounds); 3 kg ball: +2 m/s

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) 3 kg at 4 m/s sticks to a stationary 3 kg. Common speed:
(3×4)/6 = 2 m/s.
(JEE Main-level) That collision's KE loss:
Before 24 J; after ½(6)(4)=12 J → 12 J lost.
(Concept) Two identical steel balls, one moving, one at rest, elastic collision. After:
Velocity swap — the first stops, the second moves at the original speed.
(JEE Main-level) A light ball hits a heavy wall elastically head-on. The ball's speed:
Same speed, reversed direction (infinite-mass limit).
(Concept) Which quantity NEVER survives an explosion-then-reassembly? / Which always survives a collision?
KE can die; momentum always survives.
🧠 Memory tricks & everyday anchors — the 20-second revision

▶ Recap card — save for revision week

← Part 5: Power and Efficiency: How FAST You Can Do the WorkPart 7: Springs and Vertical Circles: Energy in Two Classic Stages →

Springs and Vertical Circles: Energy in Two Classic Stages

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 7 of 8 · All parts →

✪ Key points — the 30-second version

Swing a bucket of water over your head — the water stays in. Loop a plane — passengers are pushed into seats, not belts. Both are one rule about the minimum speed at the top of a vertical circle. Part 7 of the Work, Energy & Power series: two classic energy stages every exam loves.

In this card

  1. Hooke's law, simply
  2. The vertical circle's top point: the weak link
  3. The √(gR) rule, derived
  4. Energy connects the levels
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap

Hooke's Law, Simply

The vertical circle: the TOP is the weak link — gravity alone must supply the whole inward push, giving the minimum speed √(gR)

TOP: min speed √(gR) gravity pulls toward centre (helper) BOTTOM: needs √(5gR) gravity opposes (must climb out) release height h = 2.5R

pull-back force = stiffness × stretch  (F = kx)double the stretch, double the pull — and the stored energy squares (½kx², Part 3)
Letter What it means (plain words) Value / unit
F the force the spring pulls back with N
k stiffness — newtons per metre of stretch N/m
x stretch (or squeeze) from natural length m

Combined with energy: stretch stores ½kx², and releasing converts it to KE. This pairing (F = kx to find forces; ½kx² to find energy) solves every spring question.

The Vertical Circle's Top Point: The Weak Link

In a vertical circle, the top is the danger point — gravity pulls you toward the centre (helping the circle) and speed is lowest there (energy spent on climbing). The question: how slow can you go at the top and still keep the circle?

The √(gR) Rule, Derived

At the top, gravity pulls down — straight toward the centre. In the most desperate case, gravity alone supplies the entire inward push the circle demands:

mg = mv²/R  →  v_top = √(gR)the absolute minimum top speed — any slower, the circle fails and you drop

Below √(gR), gravity wants more inward pull than the circle's path can provide — the object leaves the circle (water leaves the bucket). At or above it, the track/rotation holds. One number, universal: bucket, plane, rollercoaster, satellite (whose 'circle never fails' because it's always in free fall).

Energy Connects the Levels

To find the minimum launch speed at the BOTTOM for a full loop: bottom speed must be enough to climb 2R and still have √(gR) at top. Energy: ½mv_b² = ½m(gR) + mg(2R) → v_b = √(5gR) — the famous √5, sibling of Part 4's 2.5R height rule (they're the same statement, one in speeds, one in heights).

Solved Examples

✎ Easy — Hooke. A spring (k = 400 N/m) stretched 5 cm. Pull-back force and stored energy?

Force: 400 × 0.05 = 20 N. Energy: ½(400)(0.05²) = 0.5 J.

Note: force linear (20 N), energy quadratic — different books. ✔

Answer: F = 20 N; E = 0.5 J

✎ Exam level — the bucket. Minimum speed at the top of a 1 m vertical circle (g = 10)?

√(gR): √(10 × 1) ≈ 3.16 m/s.

Feel it: one full turn per ~2 seconds — that's why you swing a bucket briskly, not lazily. ✔

Answer: ≈ 3.16 m/s

✎ JEE level — the √5 launch. A bead on a frictionless vertical loop (R = 0.8 m). Minimum bottom speed to complete the loop (g = 10)?

Energy route: ½v_b² = ½(gR) + 2gR → v_b = √(5gR) = √(5×10×0.8) = √40.

v_b ≈ 6.32 m/s.

Cross-check with Part 4: release height needed = 2.5R = 2 m → v from 2 m drop = √(2×10×2) = √40 ✔ — speeds and heights tell the same story.

Answer: v_b = √(5gR) ≈ 6.32 m/s

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

Practice set (answers hidden — try first)

(NEET-level) Spring k = 200 N/m, x = 10 cm. Force:
F = 200 × 0.10 = 20 N.
(JEE Main-level) Minimum top speed in a 0.4 m vertical circle (g = 10):
√(10 × 0.4) = 2 m/s.
(JEE Main-level) Minimum bottom speed for the same loop:
√(5 × 10 × 0.4) = √20 ≈ 4.47 m/s.
(Concept) At the top at minimum speed, the string's tension is:
Zero — gravity supplies the entire inward push.
(NEET-level) Doubling a spring's stretch multiplies its stored energy by:
4 (x²).
🧠 Memory tricks & everyday anchors — the 20-second revision

▶ Recap card — save for revision week

← Part 6: Collisions: The Great Sorting — What Survives, What DiesPart 8: The Finale: Energy in the Real World, and the Complete Formula Card →

The Finale: Energy in the Real World, and the Complete Formula Card

Aug 30, 2026

JEE/NEET Physics · Work, Energy & Power series · Part 8 of 8 · All parts →

✪ Key points — the 30-second version

A rocket burns tonnes of fuel, your body runs a marathon on a plate of rice, a dam lights a city — three systems, one ledger. The finale of the Work, Energy & Power series handles the advanced leftovers and hands you the complete formula card.

In this card

  1. Variable forces: the graph trick
  2. Energy curves: reading stability
  3. The human engine
  4. The energy economy
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap + formula card

Variable Forces: The Graph Trick

W = Fd assumed constant force. When the force changes (springs! air drag!), plot force vs distance — the work is the area under the graph. Spring work ½kx² is exactly the triangle under F = kx: ½ × base × height = ½ × x × kx. One picture unifies every variable-force case.

Energy Curves: Reading Stability

Plot a body's PE against position. Valleys = stable equilibrium (pushed away, it rolls back — a ball in a bowl). Hills = unstable (a pencil on its tip — any nudge and it leaves). Flat = neutral (a ball on a table). And a small wiggle at a valley's bottom is automatically simple harmonic motion — the bridge into the next series, Oscillations.

The Human Engine

Your body runs at ~100 W idle, ~400 W walking, ~1,000 W sprinting (elite cyclists touch 1,500 W bursts). A day's food ~9 MJ — roughly a 100 W bulb burning 24 hours. You are, quite literally, a moderately powerful heat engine with excellent snack logistics.

The Energy Economy

Chemical (fuel/food) → heat → motion/electricity, with losses at every step. A power plant: fuel → steam → turbine → electricity ≈ 40% max; an EV battery-to-wheel ≈ 85%; incandescent bulb: 5% light, 95% heat. Every 'energy crisis' discussion and star-rating sticker is this chapter at civic scale.

Solved Examples

✎ Easy — graph work. A force grows linearly from 0 to 50 N over 4 m. Work?

Area under the line = triangle = ½ × 4 × 50 = 100 J.

Cross-check: average force 25 N × 4 m = 100 J ✔

Answer: 100 J

✎ Exam level — curve reading. A PE curve has a valley at x = 2 m. At the valley floor, the force on the body is:

Force = the curve's slope — at a valley's floor, slope = 0 → zero force (equilibrium), and displaced either way, the slope pushes it back — that's stability. ✔

Answer: zero force; stable — it returns

✎ JEE level — full chain. A 60% efficient motor pumps 5,000 kg of water up 12 m each minute (g = 10). Electric power drawn?

Useful: mgh/t = 5,000×10×12 ÷ 60 = 10,000 W.

Drawn: 10,000 ÷ 0.6 ≈ 16.7 kW.

The 6.7 kW gap = motor heat — efficiency is always a heat story. ✔

Answer: ≈ 16.7 kW

⚠ Mistakes students make — and how to avoid them

This Physics in Your Daily Life

◎ This physics in your daily life

What Formula Remember
Work W = Fd·cosθ perpendicular = zero; against motion = negative
Kinetic energy ½mv² square! double speed ×4
Work-energy theorem W_total = ΔKE before/after only — path-free
Height PE mgh choose one zero level
Spring PE ½kx² stretch squared; metres!
Energy conservation KE + PE = constant (gravity/springs) friction leak = F·d → heat
Drop speed v = √(2gh) no mass anywhere
Loop minimums v_top = √(gR); v_bottom = √(5gR); h = 2.5R gravity helps at the top
Power P = W/t = Fv watts; 1 hp = 746 W
Efficiency useful ÷ input always < 100%
Collisions momentum always survives sticking = max KE loss; equal-mass elastic = swap
Variable force work = area under F-d graph ½kx² is the triangle
PE curves valley = stable, hill = unstable slope = force

Practice set (answers hidden — try first)

(NEET-level) Force rises linearly 0→30 N over 6 m. Work:
Triangle: ½ × 6 × 30 = 90 J.
(Concept) A PE curve's hill-top is what kind of equilibrium:
Unstable — any nudge and the body leaves.
(JEE Main-level) A 75% motor delivers 3 kW useful. Input power:
3 ÷ 0.75 = 4 kW.
(Concept) Why do switchback mountain roads exist?
Fixed engine power: trading distance for climbing force (P = Fv) — geography applying this chapter.
(JEE Main-level) A ball dropped from h on a spring (k): maximum compression x satisfies:
mgh = ½kx² → x = √(2mgh/k).
🧠 Memory tricks & everyday anchors — the 20-second revision

▶ Recap card — save for revision week

← Part 7: Springs and Vertical Circles: Energy in Two Classic Stages

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