You are currently viewing Vertical Motion and Free Fall: Gravity’s Signature Move
JEE Main and Advanced6 min readSep 4, 2026Updated Sep 5, 2026

Vertical Motion and Free Fall: Gravity’s Signature Move

Vertical Motion and Free Fall: Gravity’s Signature Move
6 min read · 1,102 words

JEE/NEET Physics · Motion in a Straight Line series · Part 4 of 6 · All parts →

✪ Key points — the 30-second version

  • In free fall (air ignored) everything accelerates at g ≈ 9.8 m/s² downward — mass doesn’t matter
  • The three equations survive with a = −g (up + convention) or +g (down + convention)
  • Up-and-down trips are symmetric: rise time = fall time; launch speed = landing speed
  • Maximum height: v = 0 there → H = u²/2g
  • Signs are everything: pick up as + once, then g is −, and landings below the start have negative s

Drop a coin and a key together: they hit the ground together. Heavy or light, everything falls with the same acceleration — gravity’s great democracy. Part 4 of the Motion in a Straight Line series.

In this card

  1. Free fall: the mass surprise
  2. Throwing up: the symmetric trip
  3. Maximum height and time of flight
  4. The sign convention that saves you
  5. Solved examples
  6. Common mistakes
  7. This physics in your daily life
  8. Practice set
  9. Recap

Free Fall: The Mass Surprise

Gravity pulls harder on heavier things (mg), but heavier things are also harder to accelerate (ma with bigger m) — and the two effects cancel exactly: a = g for everyone. A feather loses only because air drag cheats; in a vacuum it keeps pace with a hammer (Apollo 15 proved it on the Moon).

Throwing Up: The Symmetric Trip

Toss a ball up at u. It decelerates at g, stops for an instant at the top (v = 0, but a is STILL g — gravity never takes a break), then falls back symmetrically: rise time = fall time = u/g, landing speed = launch speed. The top is a pause, not a hover.

Maximum Height and Time of Flight

H = u²/2g · T_up = u/g · full flight (same level) = 2u/gall from v = u + at and v² = u² + 2as with v = 0 at the top
LetterWhat it means (plain words)Value / unit
gfree-fall acceleration near Earth’s surface≈ 9.8 m/s², always DOWN (sign is yours to set)
Hmaximum height above launchm
ulaunch (initial) speed upwardm/s

The Sign Convention That Saves You

Take UP as + (the usual choice for tosses). Then a = −9.8 always, up-velocities start positive and decay, and any landing BELOW the launch point has s negative. All three golden equations then work unchanged. Most vertical-motion errors are sign errors, not physics errors.

Solved Examples

✎ Easy — the drop. A stone falls from rest for 3 s. Speed and distance (g = 10)?

v = gt = 30 m/s; s = ½gt² = 45 m.

Answer: 30 m/s; 45 m

✎ Exam level — the toss. Ball thrown up at 20 m/s (g = 10). Height, time up, flight time?

H = u²/2g = 400/20 = 20 m; t_up = u/g = 2 s; full flight = 4 s.

Landing speed = 20 m/s again — perfect symmetry. ✔

Answer: H = 20 m; 4 s flight

✎ JEE level — the cliff. Ball thrown up at 15 m/s from a 20 m cliff. Time to the ground (down +, g = 10)?

Down +: u = −15, a = +10, s = +20: 20 = −15t + 5t² → t² − 3t − 4 = 0 → t = 4 s (reject −1).

4 s — the quadratic’s negative root is physics asking to be thrown backwards in time. ✔

Answer: 4 s

⚠ Mistakes students make — and how to avoid them

  • Heavy falls faster. No — mass cancels; only air resistance (ignored here) breaks the tie.
  • v = 0 at the top means a = 0. Wrong — velocity pauses, acceleration stays a full g downward the whole flight.
  • Using +g while calling up positive. With up +, g enters every equation as −9.8; mixing signs flips answers silently.
  • Forgetting displacement sign below launch. Ball landing under the start point: s is negative (up + convention) — the equation knows where the ground is only if you tell it.

This Physics in Your Daily Life

◎ This physics in your daily life

  • Water from a tap ‘beads’ into droplets that accelerate as they fall — the widening spacing between drops is a live ½gt² graph.
  • Catch a high ball and it stings more than a low one — landing speed grows with fall height (√(2gh)): your hands are doing v² = u² + 2as.
  • Amusement drop-towers are engineered near-g falls: the stomach-lift IS your body briefly in free fall, everything falling together.
  • Cricket fielders’ high catches — they start moving BEFORE the ball peaks, because rise time = fall time tells them the schedule.
  • Rainbows of fountains — designers tune jet speed u to reach height u²/2g: every fountain arc is this card in water.
One idea, three doors — open whichever clicks for you
Same concept (why everything falls at the same rate), three different ways of seeing it. If one door confuses you, try the next — at least one will stick.
Door 1 · The story way

Galileo’s legend: drop a cannonball and a musket ball from the Tower of Pisa — they land together. Gravity writes a bigger pull on the cannonball, but inertia writes a bigger refusal on it too, in exactly the same proportion. The two cancellations are perfect; the universe doesn’t check your weight before accelerating you.

Door 2 · The numbers way

Numbers: g = 9.8 m/s² for all. After 1 s: 9.8 m/s; after 2 s: 19.6; after 3 s: 29.4 — every falling object runs this exact velocity schedule, stone or boulder. Height fallen: 4.9, 19.6, 44.1 m — one timetable for the whole planet.

Door 3 · The picture way

Draw v-t for a toss: a straight line tilting down through zero — up-velocity bleeding away, zero at the top (a single point, not a shelf), then negative growing. The SAME straight line covers rise and fall: one slope (−g), one picture, symmetric either side of the zero-crossing.

Why is this happening at all? Why does mass cancel? Because gravitational force is mg (proportional to m) AND inertia is ma (proportional to m): a = mg/m = g, the m’s divide out identically. This coincidence is deep — Einstein made it the foundation of general relativity (gravity isn’t even a force, he said, just the shape of spacetime). For JEE/NEET: it’s why every free-fall problem never needs the mass.

Practice set (answers hidden — try first)

(NEET-level) Dropped from rest, speed after 2 s (g=10):
v = gt = 20 m/s.
(JEE Main-level) u = 30 m/s up. Time back to the hand:
T = 2u/g = 6 s.
(NEET-level) Height reached at u = 20 (g=10):
H = 400/20 = 20 m.
(Concept) At the highest point of a throw:
v = 0, a = g downward.
(JEE Main-level) Fall from 45 m: time (g=10) =
45 = 5t² → 3 s.
🧠 Memory tricks & everyday anchors — the 20-second revision

  • free fall: a = g for ALL masses
  • up + convention: a = −9.8 throughout
  • top of flight: v = 0, a = g still
  • H = u²/2g, T_flight = 2u/g (same level)
  • symmetry: rise = fall, launch speed = landing speed
  • 🔁 all masses fall at g
  • 🔁 v = 0 but a = g at the top
  • 🔁 H = u²/2g · T = 2u/g
▶ Recap card — save for revision week

  • 🧠 Chant: ‘gravity never rests — even at the top’.
  • 🧠 Symmetry: ‘up-mirror is down-mirror’.
  • 🧠 g ≈ 10 for quick maths, 9.8 for accuracy.
  • 🏠 Daily: tap-water drop spacing = the ½gt² graph live.
  • 🏠 Daily: fielders run early because rise time = fall time.

Quick revision

  • In free fall (air ignored) everything accelerates at g ≈ 9.8 m/s² downward — mass doesn’t matter
  • The three equations survive with a = −g (up + convention) or +g (down + convention)
  • Up-and-down trips are symmetric: rise time = fall time; launch speed = landing speed
  • Maximum height: v = 0 there → H = u²/2g
  • Signs are everything: pick up as + once, then g is −, and landings below the start have negative s
  • Free fall: the mass surprise
ShareTelegramX

Have a doubt on this topic?